Two lenses, one converging with focal length 10.0 cm and one diverging with focal length -5.0 cm, are placed 13.0 cm apart. An object is placed 30.0 cm in front of the converging lens. Determine the position of the final image formed.​

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Two lenses, one converging with a focal length of 10.0 cm and one diverging with a focal length of -5.0 cm, are placed 13.0 cm apart, the position of the final image formed is mathematically given as

u=70.645

What is the position of the final image formed.​?

Generally, the equation for the convex lens is mathematically given as

I/f=1/u-1/v

Therefore

1/20=1/u-(1/-61)

u=29.76cm

In conclusion, For concave lens

1/-10=1/u-1/8.76

u=87.6/1.2

u=70.645

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