In the diagram below, $BE=EC=DF,$ and $\triangle ADF$ has the same area as $\triangle DEF.$ If rectangle $DXYF$ has area $42,$ what is the area of $\triangle ABC$? [asy] size(0,4cm); pair B=(-3,0); pair C=(5,0); pair A=(2,3); pair D=(A+B)/2; pair E=(B+C)/2; pair F=(C+A)/2; pair W=(-0.5,3); pair X=(-0.5,0); pair Y=(3.5,0); pair Z=(3.5,3); draw(A--B--C--cycle); draw(D--E--F--cycle); dot(A); dot(B); dot(C); dot(D); dot(E); dot(F); dot(X); dot(Y); //dot(W); dot(Z); label("$A$",A,N); label("$B$",B,SW); label("$C$",C,SE); label("$D$",D,NW); label("$E$",E,S); label("$F$",F,NE); draw(D--X,dashed); draw(F--Y,dashed); label("$X$",X,S); label("$Y$",Y,S); //label("$W$",W,N); //label("$Z$",Z,N); draw(X+(0.25,0)--X+(0.25,0.25)--X+(0,0.25)); draw(Y-(0.25,0)--Y+(-0.25,0.25)--Y+(0,0.25)); //draw(W+(0.25,0)--W+(0.25,-0.25)--W+(0,-0.25)); //draw(Z+(-0.25,0)--Z+(-0.25,-0.25)--Z+(0,-0.25)); [/asy]

Respuesta :

Lanuel

Based on the calculations, the area of triangle ABC is equal to 84 units².

How to calculate the area of a triangle?

Mathematically, the area of a triangle can be calculated by using this formula:

Area = 1/2 × b × h

Where:

  • b is the base area.
  • h is the height.

By critically observing the diagram (see attachment), we can logically deduce that ΔABC can be divided into four (4) congruent triangles i.e ΔADF, ΔBDE, ΔDEF, and ΔEFC. Also, ΔDEF is half the area of rectangle DXYF.

Thus, the area of ΔABC is given by:

ΔABC = 42/2 × 4

ΔABC = 21 × 4

ΔABC = 84 units².

Read more on area of triangle here: brainly.com/question/21917592

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Complete Question:

In the diagram below, BE = EC = DF, and ΔADF has the same area as ΔDEF. If rectangle DXYF has area 42 what is the area of ΔABC? ​

Ver imagen Lanuel