Lina picks a 4 digit number.
The number is more than 5000.
The number is odd.
The second digit is a prime number.

How many different possible numbers could Lina pick?

Respuesta :

Using the Fundamental Counting Theorem, it is found that there are 1000 possible numbers that Lina could pick.

What is the Fundamental Counting Theorem?

It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

In this problem:

  • The number is more than 5000, hence the first digit can be 5, 6, 7, 8 or 9, hence [tex]n_1 = 5[/tex].
  • The second digit is prime, that is, 2, 3, 5 or 7, hence [tex]n_2 = 4[/tex].
  • For the third digit, there are no restrictions, hence [tex]n_3 = 10[/tex].
  • The number is odd, hence the fourth digit can be 1, 3, 5, 7 or 9, hence [tex]n_4 = 5[/tex].

Hence the number of combinations is given by:

N = 5 x 4 x 10 x 5 = 1000

More can be learned about the Fundamental Counting Theorem at https://brainly.com/question/24314866

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