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An expression which gives the number of cookies that Priti still has at the end of third period is 2C/5.
How to determine the expression?
For the first period, we have:
First period = 1/4 × C
First period = C/4.
Remaining = C - C/4 = 3C/4
For the second period, we have:
Second period = 1/5 × 3C/4
Second period = 3C/20.
Remaining = 3C/4 - 3C/20 = 12C/20
For the third period, we have:
Third period = 2/3 × 12C/20
Third period = 24C/60.
Third period = 2C/5.
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The following expressions give the number of cookies, in terms of c, that Priti still has at the end of the third period are B. c/5.
How do you figure out the expression?
- The first time period includes:
- Initial = 1/4 * C
- The first period equals C/4.
- What's left: =C-C/4=3C/4
- The second period is as follows:
- Period two equals 1/5*3C/4.
- 3C/20 is the second period.
- The third period is as follows:
- The third period is equal to 2/3 * 12C/ 20.
- Period three = 24C/60.
- Third semester = 2C/5.
- Here is further information on expressions:
- Number Left = 3C/4 - 3C/20 = 12C/2
Read more about the period of time:
https://brainly.com/question/12189823
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