contestada

Using the quadratic formula to solve x2 = 5 – x, what are the values of x?
StartFraction negative 1 plus-or-minus StartRoot 21 EndRoot Over 2 EndFraction
StartFraction negative 1 plus-or-minus StartRoot 19 EndRoot i Over 2 EndFraction
StartFraction 5 plus-or-minus StartRoot 21 EndRoot Over 2 EndFraction
StartFraction 1 plus-or-minus StartRoot 19 EndRoot i Over 2 EndFraction
Mark this and return

Respuesta :

mani82ebra

Answer:

x²=5-x

x²+x-5=0

1x²+1x²-5=0

[ax²+bx²+c=0]

∆=b²-4ac

∆=1²-4(-5)(1)=1+20=21

x=(-b±√∆)/2a

x=(-1±√21)/2

meaning:

x=(-1+√21)/2 or x=(-1-√21)/2

Otras preguntas