Respuesta :

Answer:

89.6 L

Explanation:

In normal conditions,

For every 1 mole of carbon dioxide at STP, it occupies 22.4 L of volume.

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Solving :

⇒ 1 mole : 22.4 L

⇒ 1 × 4 : 22.4 × 4

⇒ 4 moles : 89.6 L