When the mass of atoms are given, we can easily find out the simplest (Empirical) formula of the molecule.
Here, the Simplest (Empirical) formula for the given alkane is [tex]C_3H_8[/tex]
What is Empirical Formula ?
Empirical formula is defined as the formula of a compound which gives the simple whole number ratio of the atoms of various elements present in one molecule of compound.
For this problem, we are given the mass in grams of each element.
Begin by finding the moles of each :
No. of mole = Given weight / Atmoic Weight
So,
No. of Moles of Carbon = 9/12 = 0.75
No. of Moles of Hydrogen = 2/1 = 2
Next, derive the Carbon-to-Hydrogen molar ratio by dividing by the lesser number of moles :
C = 0.75/0.75 = 1
H = 2/0.75 = 2.66
The ratio is 1.000 mol of Carbon to 2.66 mol of Hydrogen ([tex]C_1H_2._6_6[/tex]).
Finally, multiply the ratio by three to get the smallest possible whole number subscripts while still maintaining the correct Carbon-to-Hydrogen ratio :
3 ([tex]C_1H_2._6_6[/tex]) = ([tex]C_3H_7._9_8[/tex]) = [tex]C_3H_8[/tex]
Hence, the Simplest (Empirical) formula for the given alkane is [tex]C_3H_8[/tex]
Learn more about Empirical formula here ;
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