12. As depicted in the figure below, a stone is projected to a cliff of height h with an initial speed of 42m/s directed at angle = 600 above the horizontal. The stone strikes at A, 5 second after launching. Find A the height h of the cliff, B the speed of the stone just before impact at A, and C the maximum height H reached above the ground D Find tutal displacement from the initial point to A

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onyebuchinnaji onyebuchinnaji · Answer 1 · 2022-06-13T21:52:40+02:00

(a) The height h of the cliff is determined as 59.36 m.

(b) The speed of the stone just before impact at A is 87.9 m/s.

(c) The maximum height H reached above the ground is 126.86 m.

The height of the cliff is calculated as follows;

h = ut - ¹/₂gt²

h = (42 x sin60)(5) - ¹/₂(9.8)(5)²

h = 59.36 m

vf = vi + gt

vfy = (42sin60) + (9.8)(5)

vfy = 85.37 m/s

vfx = vxi = 42 x cos60 = 21 m/s

V = √(21² + 85.37²)

V = 87.9 m/s

H = (u²sin²θ)/2g

H = (42² x (sin60)²)/(2 x 9.8)

H = 67.5 m

Height reached above the ground = 67.5 m + 59.36 m = 126.86 m

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