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The following table shows the number of hours some middle school students in two cities spend texting each week: City A 9 27 17 24 21 12 25 25 18 City B 6 20 26 15 23 25 14 14 11 Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (5 points) Part B: Are there any outliers present for either data set ?Justify your answer. (5 points)

The following table shows the number of hours some middle school students in two cities spend texting each week City A 9 27 17 24 21 12 25 25 18 City B 6 20 26 class=

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A. Five-number summary for City A and B are given below. IQR for City A is 10.5; IQR for City B is 11.5

B. There are no outliers present in either data set.

What is the Five-number Summary?

The values in the five-number summary include, lower and upper quartiles, max and min values, and the median.

What is the Interquartile Range (IQR)?

Interquartile range (IQR) = upper quartile (Q3) - lower quartile (Q1)

What is an Outlier?

Outlier of a data set is any value that is lower than Q1 - 1.5 × IQR or greater than Q3 + 1.5 × IQR.

The five-number summary for City A, 9, 27, 17, 24, 21, 12, 25, 25, 18, is:

  • Minimum: 9
  • Quartile Q1: 14.5
  • Median: 21
  • Quartile Q3: 25
  • Maximum: 27

IQR = 25 - 14.5 = 10.5

Outlier for City A:

Q1 - 1.5 × IQR = 14.5 - 1.5 × 10.5 = -1.25

Q3 + 1.5 × IQR = 25 + 1.5 × 10.5 = 40.75

No value is less than -1.25 or greater than 40.75, therefore, there is no outlier in City A.

The five-number summary for City B, 6, 20, 26, 15, 23, 25, 14, 14, 11,  is:

  • Minimum: 6
  • Quartile Q1: 12.5
  • Median: 15
  • Quartile Q3: 24
  • Maximum: 26

IQR = 24 - 12.5 = 11.5

Outlier for City B:

Q1 - 1.5 × IQR = 12.5 - 1.5 × 11.5 = -4.75

Q3 + 1.5 × IQR = 24 + 1.5 × 11.5 = 41.25

No value is less than -4.25 or greater than 41.25, therefore, there is no outlier in City B.

Learn more about the five-number summary on:

https://brainly.com/question/24809873

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