Respuesta :
Let's do
#a
[tex]\\ \rm\Rrightarrow 3^{-3}\times 3^{-2}[/tex]
[tex]\\ \rm\Rrightarrow 3^{-3-2}[/tex]
[tex]\\ \rm\Rrightarrow 3^{-5}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{1}{3^5}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{1}{243}[/tex]
#b
[tex]\\ \rm\Rrightarrow \dfrac{-3}{(-3)^2}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{-3}{9}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{-1}{3}[/tex]
[tex]\mathbb{PROBLEM:}[/tex]
Evaluate:
a. 3 to the -3 power x 3 to the -2 power
b. -3/(-3) to the 2 power
[tex]\mathbb{SOLUTION:}[/tex]
a. 3 to the -3 power x 3 to the -2 power
[tex] \tt \: {3}^{ - 3} \times {3}^{ - 2} [/tex]
[tex] \tt \: {3}^{ - 3 - 2} [/tex]
[tex] \tt {3}^{ - 5} [/tex]
[tex] \tt \frac{1}{3.5} [/tex]
[tex]\underline \bold\green{ \frac{1}{243} }[/tex]
b. -3/(-3) to the 2 power
[tex] \tt \: \frac{ \: \: - 3}{ \: ( - 3) {}^{2} } [/tex]
[tex] \tt \: \frac{ \: \: - 3}{ 9} [/tex]
[tex] \underline \bold \green{ \frac{ \: - 1}{3 \: } }[/tex]
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