The acceleration of the car that came to a stop from a speed of 16 m/s in a time of 2.3 seconds is -6.96m/s² (option D).
The acceleration of a moving substance can be calculated by dividing the change in velocity of the substance by the time.
Acceleration (a) = ∆V/t
Where;
a = -16m/s ÷ 2.3s
a = -6.96m/s²
Therefore, the acceleration of the car that came to a stop from a speed of 16 m/s in a time of 2.3 seconds is -6.96m/s².
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