A car came to a stop from a speed of 16 m/s in a time of 2.3 seconds. What
was the acceleration of the car?
A. -13.7 m/s²
B. -9.80 m/s2
OC. -4.12 m/s²
OD. -6.96 m/s²

Respuesta :

The acceleration of the car that came to a stop from a speed of 16 m/s in a time of 2.3 seconds is -6.96m/s² (option D).

How to calculate acceleration?

The acceleration of a moving substance can be calculated by dividing the change in velocity of the substance by the time.

Acceleration (a) = ∆V/t

Where;

  • ∆V = change in velocity
  • t = time

a = -16m/s ÷ 2.3s

a = -6.96m/s²

Therefore, the acceleration of the car that came to a stop from a speed of 16 m/s in a time of 2.3 seconds is -6.96m/s².

Learn more about acceleration at: https://brainly.com/question/12550364

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