How many kilojoules of heat would be required to fully melt a 0.834 m³ block of ice , provided that the density of ice is 917 kg / m³ ? H₂O ( s ) → H₂O ( 1 ) AH = 6.01 kJ

How many kilojoules of heat would be required to fully melt a 0834 m block of ice provided that the density of ice is 917 kg m HO s HO 1 AH 601 kJ class=

Respuesta :

2.54 × 10⁵ kJ of heat are required to fully melt a 0.834 m³ block of ice, with a density of 917 kg / m³.

What is melting?

Melting is a physical change in which solids turn into liquids.

  • Step 1. Calculate the mass of ice.

We have a block of 0.834 m³ of ice with a density of 917 kg/m³.

0.834 m³ × 917 kg/m³ = 765 kg = 7.65 × 10⁵ g

  • Step 2. Convert 7.65 × 10⁵ g to moles.

We will use the molar mass of water.

7.65 × 10⁵ g × (1 mol/18,02 g) = 4.24 × 10⁴ mol

  • Step 3. Calculate the heat required to melt 4.24 × 10⁴ moles of water.

According to the thermochemical equation, 6.01 kJ are required to melt 1 mol of water.

4.24 × 10⁴ mol × (6.01 kJ/mol) = 2.54 × 10⁵ kJ

2.54 × 10⁵ kJ of heat are required to fully melt a 0.834 m³ block of ice, with a density of 917 kg / m³.

Learn more about melting here: https://brainly.com/question/40140

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