[tex]\frak{Hi!}[/tex]
[tex]\orange\hspace{300pt}\above2[/tex]
We have the equation [tex]\large\boldsymbol{\sf{\displaystyle\frac{3}{4}x-12=-18}}[/tex].
First we should add 12 to both sides of the equation.
[tex]\large\boldsymbol{\sf{\displaystyle\frac{3}{4}x=-18+12}}[/tex]. Simplify
[tex]\large\boldsymbol{\sf{\displaystyle\frac{3}{4}x=-6}}[/tex].
This done, let's multiply the equation by 4. You'll see why
[tex]\large\boldsymbol{\sf{\displaystyle\frac{3}{\not4}x\times\not4=-6\times4}}[/tex]
Did you see how on the left, the 4's cancelled? That's
because dividing by 4 and then multiplying the same
number, or the result, by 4, are operations that undo each
other.
This being said, let's finish solving this equation in terms of x
[tex]\large\boldsymbol{\sf{3x=-24}}[/tex]. See how this works?
Now, remember that we ought to use inverse operations
to solve for x. These are operations that undo each other.
So if x is multiplied by 3, we should... divide by 3!
Also, please keep in mind that we can only divide the left side
by 3 if we divide the right side by 3.
[tex]\large\boldsymbol{\sf{\displaystyle\frac{3x}{3}=\displaystyle\frac{-24}{3}}}[/tex]. Once again the 3s on the left cancel, leaving
x. Wait! Isn't that what we wanted? Yepp, sure!
The right side is now -8. Thus,
[tex]\large\boldsymbol{\sf{x=-8}}[/tex]
[tex]\orange\hspace{300pt}\above3[/tex]
