A tank car contains of acetone (density = 0.785 g/cm3). What is the volume of a full tank car, in m3, which contains 3.22 x 104 kg of acetone?

show the work please!​

Respuesta :

Taking into account the definition of density, the volume of a full tank car which contains 3.22×10⁴ kg of acetone is 41.02 m³.

Definition of density

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

[tex]density=\frac{mass}{volume}[/tex]

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

Volume of a full tank car

In this case, you know that:

  • Density= 0.785 [tex]\frac{g}{cm^{3} }[/tex]
  • mass= 3.22×10⁴ kg=  32,200,000 g (being 1 kg= 1000 g)
  • Volume= ?

Replacing in the definition of density:

[tex]0.785 \frac{g}{cm^{3} }=\frac{32,200,000 g}{volume}[/tex]

Solving:

volume×0.785[tex]\frac{g}{cm^{3} }[/tex]= 32,200,000 g

volume=[tex]\frac{32,200,000 g}{0.785 \frac{g}{cm^{3} }}[/tex]

volume= 41,019,108.28 cm³=  41.01910828 m³≅ 41.02 m³ (being 1 m³ = 1000000 cm³)

In summary, the volume of a full tank car which contains 3.22×10⁴ kg of acetone is 41.02 m³.

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