Answer:
[tex]-4\sqrt{2} m[/tex]
Step-by-step explanation:
Similar question to the previous one you asked, and I swear I will not make the same mistake again :)
First we will find the displacement at t = 0 and t = 1 to find both displacements.
t = 0,
[tex]x(0)=4cos(\pi (0)+\frac{\pi }{4} )=4cos(\frac{\pi }{4} )\\=4(\frac{\sqrt{2} }{2} )\\=2\sqrt{2} m[/tex]
t = 1,
[tex]x(1)=4cos(\pi (1)+\frac{\pi }{4} )=4cos(\pi +\frac{\pi }{4} )\\=4(-\frac{1}{\sqrt{2} } )\\=-\frac{4}{\sqrt{2} }[/tex]
Total Displacement = Final Position - Initial Position
= x(1) - x(0)
= [tex]-\frac{4}{\sqrt{2} } -2\sqrt{2} \\=-4\sqrt{2} m[/tex]
