simplify completely
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[tex]\dfrac{x^2+12x+35}{3x+15}=\dfrac{x^2+12x+35}{3(x+5)}=\dfrac{x^2+5x+7x+35}{3(x+5)}=\dfrac{x(x+5)+7(x+5)}{3(x+5)}=\\=\dfrac{(x+5)(x+7)}{3(x+5)}=\dfrac{x+7}{3}[/tex]
Answer:
(x+7) / 3
Step-by-step explanation:
Factorise the Top half to give :
x² + 12x+ 35 = (x+5)(x+7)
Factorise the bottom half to give :
3(x+5)
Cancel (x+5) from top and bottom to give :
(x+7) / 3
So our final answer is Option 3
Hope this helped and have a good day