a)The total distance she walks will be 1100 m.
b)The magnitude and direction of the budgie's path will be 854.4 m at 69.44°.
c)Sally's average speed for the journey will be 2.82 m/sec
d)The average velocity of Sally's budgie willl be 2.19 m/sec North of East.
Displacement is defined as the shortest distance between the two points.
Distance travelled in north direction,d₁ = 8.0 x 10² m
Time elapsed travelled in north direction,t₁ = 5.0 minutes
Distance travelled in east direction,d₂ = 0.30 km = 3.0 × 10² m
Time elapsed travelled in east direction,t₂= 1.5 minutes
The total distance she walks,d =? m
The magnitude and direction of the budgies path will be, D
Sally's average speed for the journey, [tex]\rm S_{avg}[/tex]
The average velocity of Sally's budgie,[tex]\rm V_{avg}[/tex]
a)
The total distance she walks is found as;
d=d₁+d₂
d=800 m +300 m
d = 1100 m
b)
The magnitude and direction of the budgies path will be;
[tex]\rm D = \sqrt{d_1 ^2 + d_2^2 } \\\\ D = \sqrt{800^2 +300^2 } \\\\ D = 854.4 \ m[/tex]
The direction of the displacement is;
[tex]\rm \theta = tan^{-1} \frac{800}{300} \\\\ \theta = tan^{-1}(2.6) \\\\ \theta = 69.44 ^ 0[/tex]
c)journey is found as;
Sally's average speed for the
[tex]\rm S_{avg} = \frac{d}{t} \\\\ S_{avg} =\frac{100}{300+900} \\\\ S_{avg} =2.82 \ m/sec[/tex]
d)
The average velocity of Sally's budgie is found as;
[tex]\rm V_{avg} = \frac{854.4}{300+ 900 } \\\\ V_{avg} = 2.19 \ m/sec[/tex] North of east
Hence, the total distance she walks, the magnitude and direction of the budgie's path, Sally's average speed, and the average velocity of Sally's budgie will be 1100 m,854.4 m at 69.44°,2.82 m/sec, and 2.19 m/sec North of East.
To learn more about displacement refer to the link;
https://brainly.com/question/10919017
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