The emf of the battery will be 2.955 V. The rate of change of magnetic flux linked with the coil is responsible for generating emf.
Electromagnetic induction is what causes the induced voltage. Electromagnetic induction generates emf (induced voltage) by subjecting a conductor to a magnetic field.
Given data;
Voltage,v = 200 v
Resistance, r=600 ohms
Internal resistance,R = 3 ohms
The EMF of the battery is found as follows;
E = {vR}/{R+r}
E = 200×3/(3 + 200)
E = 2.955 V
Hence, the emf of the battery will be 2.955 V.
To learn more about the induced voltage refer to the link;
https://brainly.com/question/19482771
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