The critical value and the conclusion are mathematically given as
z_{0.05}=1.960 and z<Zcritical, therefore we Reject H_o
a)Test statistic z=-3.32
Claim: p< 0.5
a=0.05
critical value z_{0.05}
z_{0.05}=1.960
b)
z<Zcritical,
Beause z=-3.32< z_{0.05}=1.960 Reject H_o
In conclusion,
z_{0.05}=1.960 and z<Zcritical, therefore we Reject H_o
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