In a clinical trial of a drug intended to help people stop smoking, 126 subjects were treated with the drug for 13 weeks, and 15 subjects experienced abdominal pain. If someone claims that more than 8% of the drug users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.19 as an alternative value of p, the power of the test is 0.95. Interpret this value of the power of the test.
The power of 0.95 shows that there is a ....% chance of rejecting the
▼
null
alternative
hypothesis of p

enter your response here when the true proportion is actually

enter your response here. That is, if the proportion of users who experience abdominal pain is actually

enter your response here, then there is a

enter your response here% chance of supporting the claim that the proportion of users who experience abdominal pain is
▼
less
greater
than 0.08.

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ogorwyne ogorwyne · Answer 1 · 2022-07-12T21:33:57+02:00

The answer to the question has to be filled into the blank as

The power of 0.95 shows that there is a 95% chance of rejecting the null hypothesis if p = 0.08 when the true proportion is actually 0.15. That is, if the proportion of users who experience abdominal pain is actually 0.15. then there is a 95% chance of supporting the claim that the proportion of users who experience abdominal pain is greater than 0.08

This is described as the likelihood of the test correctly rejecting the null hypothesis on the basis that the alternative hypothesis is correct.

This question requires us to fill in the blank with the details that we have been given.