AD= in
Help me please, stuck on this question. Thankss
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Using the cosine ratio, the value of AD in the diagram is: 2√3π in.
If we have the following given in a right triangle like triangle ADC in the diagram:
AC = 4π (hypotenuse)
AD = ? (adjacent side)
The cosine ratio, CAH would be applied, which is:
Cos 30 = adjacent/hypotenuse
Cos 30 = AD/4π
AD = cos 30 × 4π = √3/2 × 4π [cos 30 = √3/2]
AD = 2√3π in.
Learn more about the cosine ratio on:
https://brainly.com/question/15793827
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