Respuesta :
Answer:
The linear equation for the line which passes through the points given as (-2,8) and $(4,6), is written in the point-slope form as [tex]$y=-\frac{1}{3} x-\frac{26}{3}$[/tex].
Step-by-step explanation:
A condition is given that a line passes through the points whose coordinates are (-2,8) and (4,6).
It is asked to find the linear equation which satisfies the given condition.
Step 1 of 3
Determine the slope of the line.
The points through which the line passes are given as (-2,8) and (4,6). Next, the formula for the slope is given as,
[tex]$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$[/tex]
Substitute [tex]$6 \& 8$[/tex] for [tex]$y_{2}$[/tex] and [tex]$y_{1}$[/tex] respectively, and 4&-2 for [tex]$x_{2}$[/tex] and [tex]$x_{1}$[/tex] respectively in the above formula. Then simplify to get the slope as follows, [tex]$m=\frac{6-8}{4-(-2)}$[/tex]
[tex]$\begin{aligned}&m=\frac{-2}{6} \\&m=-\frac{1}{3}\end{aligned}$[/tex]
Step 2 of 3
Write the linear equation in point-slope form.
A linear equation in point slope form is given as,
[tex]$y-y_{1}=m\left(x-x_{1}\right)$[/tex]
Substitute [tex]$-\frac{1}{3}$[/tex] for m,-2 for [tex]$x_{1}$[/tex], and 8 for [tex]$y_{1}$[/tex] in the above equation and simplify using the distributive property as follows, [tex]y-8=-\frac{1}{3}(x-(-2))$\\ $y-8=-\frac{1}{3}(x+2)$\\ $y-8=-\frac{1}{3} x-\frac{2}{3}$[/tex]
Step 3 of 3
Simplify the equation further.
Add 8 on each side of the equation [tex]$y-8=-\frac{1}{3} x-\frac{2}{3}$[/tex], and simplify as follows, [tex]$y-8+8=-\frac{1}{3} x-\frac{2}{3}+8$[/tex]
[tex]$y=-\frac{1}{3} x-\frac{2+24}{3}$\\ $y=-\frac{1}{3} x-\frac{26}{3}$[/tex]
This is the required linear equation.
