The molarity of the potassium hydroxide required to neutralize 60.0 mL of 0.0100 M H3PO4 is 0.02M.
The molarity of a solution can be calculated using the following formula:
CaVa = CbVb
Where;
60 × 0.0100 = 30 × Cb
0.6 = 30Cb
Cb = 0.6/30
Cb = 0.02M
Therefore, molarity of the potassium hydroxide required to neutralize 60.0 mL of 0.0100 M H3PO4 is 0.02M.
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