Answer:
Hence the expression [tex]$(3r-8)(11r+1)=33r^2-85r-8$[/tex].
Step-by-step explanation:
Explanation
[tex]$\frac{\begin{matrix}{} & {} & 3r & - & 8 \\ \times & {} & 11r & + & 1 \\ \end{matrix}}[/tex]
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[tex]{\frac{\begin{matrix}{} & {} & 3r & - & 8 \\ 33{{r}^2} & - & 88r & {} & {} \\ \end{matrix}}{\begin{matrix}33{{r}^2} & - & 85r & - & 8 \\ \end{matrix}}}$[/tex]