Answer:
Hence the expression [tex]$(3rs-7)(3rs-4)=9r^2s^2-33rs+28$[/tex]
Step-by-step explanation:
Explanation
[tex]$\begin{matrix}{} & {} & {} & {} & 3rs & - & 7 \\ \times & {} & {} & {} & 3rs & - & 4 \\ \end{matrix}$[/tex]
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[tex]$\begin{matrix}{} & {} & {} & - & 12rs & + & 28 \\ {} & {} & 9{{r}^2}{{s}^2} & - & 21rs & {} & {} \\ \end{matrix}$[/tex]
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[tex]$\begin{matrix}{} & {} & 9{{r}^2}{{s}^2} & - & 33rs & + & 28 \\ \end{matrix}$[/tex]