Answer:
The product is the difference of squares is [tex]$\left(5k+6\right)\left(5k-6\right)=25{{k}^2}-36$[/tex]
Step-by-step explanation:
Explanation
[tex]$\begin{aligned}&(5 k+6)(5 k-6)=(5 k)^{2}-(6)^{2} \\&(5 k+6)(5 k-6)=25 k^{2}-36\end{aligned}$[/tex]