The probability that he will use both bus and the train among bus, cab, train is 0.11.
Given There are 3 choices to people each among bus, cab, train for his trip home.
Probability is the likeliness of happening an event among all the events possible. The value of probability lies between 0 and 1. The formula to calculate probability is as under:
Probability= number of things/ total things.
The value of probability cannot be negative.
Number of buses=3
Number of cab=3
Number of train=3
Probability that he will go through train and bus is 3/9*3/9
=9/81
=1/9
=0.11
Hence the probability that he will travel with bus and train is 0.11.
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Question is incomplete as it includes:
What is the probability that he will use both train and bus?
