Respuesta :
Answer:
[tex]y=\dfrac {60} {x}[/tex] or [tex]xy=60[/tex] (depending on your teacher's format preference)
Step-by-step explanation:
Proportionality background
Proportionality is sometimes called "variation". (ex. " 'y' varies inversely as 'x' ")
There are two main types of proportionality/variation:
- Direct
- Inverse.
Every proportionality, regardless of whether it is direct or inverse, will have a constant of proportionality (I'm going to call it "k").
Below are several different examples of both types of proportionality, and how they might be stated in words:
- [tex]y=kx[/tex] y is directly proportional to x
- [tex]y=kx^2[/tex] y is directly proportional to x squared
- [tex]y=kx^3[/tex] y is directly proportional to x cubed
- [tex]y=k\sqrt{x}}[/tex] y is directly proportional to the square root of x
- [tex]y=\dfrac {k} {x}[/tex] y is inversely proportional to x
- [tex]y=\dfrac {k} {x^2}[/tex] y is inversely proportional to x squared
From these examples, we see that two things:
- things that are directly proportional -- the thing is multiplied to the constant of proportionality "k"
- things that are inversely proportional -- the thing is divided from the constant of proportionality "k".
Looking at our question
In our question, y is inversely proportional to x, so the equation we're looking at is the following [tex]y=\dfrac {k} {x}[/tex].
It isn't yet clear what the constant of proportionality "k" is for this situation, but we are given enough information to solve for it: "When y=12, x=5."
We can substitute this known relationship pair, and find the "k" that relates this pair of numbers:
Solving for k, and finding the general equation
General Inverse variation equation...
[tex]y=\dfrac {k} {x}[/tex]
Substituting known values...
[tex](12)=\dfrac {k} {(5)}[/tex]
Multiplying both sides by 5...
[tex](12)*5= \left ( \dfrac {k} {5} \right ) *5[/tex]
Simplifying/arithmetic...
[tex]60=k[/tex]
So, for our situation, k=60. So the inverse proportionality relationship equation for this situation is [tex]y=\dfrac {60} {x}[/tex].
The way your question is phrased, they may prefer the form: [tex]xy=60[/tex]