Respuesta :
Lowest score earned to be qualified for an interview is 92.82
X : Marks scored in interview
X ~ N(80,100)
Here we need to find x such that P(X > x) = 0.10
using standard normal table,
we get P( z > 1.282) = 0.10
It's always easy to use Standard normal distribution to solve questions of normal distribution because standard normal is special case of normal distribution with mean 0 and standard deviation 1.
To convert x (which follows Normal distribution) to standard normal use: [tex]\frac{x-\mu}{\sigma} \sim N(0,1)[/tex]
so, [tex]z = 1.282 = \frac{x-\mu}{\sigma}[/tex]
hence,
[tex]x = 1.282 * \sigma + \mu \\x = 1.282 * 10+_80 \\x = 92.82 \\[/tex]
Hence Lowest score earned to be qualified for an interview is 92.82
To learn more about Normal Distribution visit:
https://brainly.com/question/4079902
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