The two negative odd integers such that 5 times the first plus the square of the second equals -14 are: -3 and -1.
In a multiplication or division issue, an odd number of negatives will always result in a negative odd integer.
A negative odd integer carries a negative sign and is not exactly divisible by 2.
According to the question, an equation can be formed as follows:
[tex]5a+b^{2}=-14[/tex]
Here, a and b are the two negative odd integers.
Let a= -3 and b= -1,
[tex]5a+b^{2}=5(-3)+(-1)^{2}\\[/tex]
= -15+1
= -14
Thus, the required negative odd integers are -3 and -1.
Learn more about negative odd integers here:
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