The slope m = 3/2 and the y-intercept = ( 0, -6 ).
The graph is a solid line and shaded area below the boundary line since y is less than (3/2)x - 6.
What is the Graph the solution set of the inequality?
Given that:
3x -2y ≥ 12
First we write the inequality in slope intercept form y = mx + b.
Solve for y
3x -2y ≥ 12
-2y ≥ 12 - 3x
Now, divide each term by -2
y ≤ -6 + 3x/2
We re-arrange
y ≤ (3/2)x - 6
Using the slope intercept form y = mx + b. we can see that;
m = 3/2
b = -6
Hence, the slope m = 3/2 and the y-intercept = ( 0, -6 ).
The graph is a solid line and shaded area below the boundary line since y is less than (3/2)x - 6.
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