To draw the median of the triangle from vertex A, the mid point of BC must be determined. The median of the vertex A is given at (-1/2, 1). See explanation below.
How you would draw the median of the triangle from vertex A?
Recall that B = (3, 7)
and C = (-4, -5).
- Note that when you are given coordinates in the format above, B or C = (x, y)
- Hence the mid point of line BC is point D₁ which is derived as:
D₁ [tex][ (\frac{3-4}{2})[/tex] , [tex](\frac{7-5}{2}) ][/tex] - hence, the Median of the Vertex A = (-1/2, 1).
Connecting D' and A gives us the median of the vertex A. See attached graph.
What is the length of the median from C to AB?
Recall that
A → (4, 2); and
B → (3, 7)
Hence, the Midpoint will be
[tex][(\frac{4+3}{2} )[/tex], [tex](\frac{2+7}{2} )][/tex]
→ [tex](\frac{7}{2}, \frac{9}{2} )[/tex]
Recall that
C → (-4, 5)
Hence,
[tex]\overline{C D_{2} }[/tex] = [tex]\sqrt{[(-4 -\frac{7}{2} })^{2} + (-5-\frac{9}{2} )^{2} ][/tex]
Simplified, the above becomes
= √(586)/2)
= 24.2074/2
= 12.1037
The length of the Median from C to AB ≈ 12
Learn more about Vertex at;
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