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Two people are dragging a canoe on a beach using light ropes. Person 1 applies a
force of 60.0N [Forward] and person 2 applies a force of 90.0N [Forward]. The
friction exerted by the beach on the canoe is 85.0N. Determine the net force of the
canoe.
a) 50.0 N [forward]
Ob) 6.50 N [backward]
c) 6.50 N [forward]
d) 65.0 N [forward]

Respuesta :

pstnonsonjoku

The net force on the canoe is obtained as 65.0 N [forward]

What is the frictional force?

The frictional force is the force that opposes motion. We know that the net force is the actual force that moves the canoe in a given direction.

Hence, the total force acting in the forward direction = 60.0N + 90.0N = 150 N and the total backwards force =  85.0N

Net force =  150 N - 85.0N = 65.0 N [forward]

Learn more about net force:https://brainly.com/question/18031889

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