The volume of 0.8 M solution of citric acid required would be 75mL.
Given:
Concentration of citric acid =0.8M
Mass of baking soda = 15 g
Balanced chemical equation for the reaction of baking soda(NaHCO₃ ) with citric acid (C₆H₈O₇) is:
C₆H₈O₇ + 3NaHCO₃ -----> 3H₂O + 3CO₂ + Na₃C₆H₅O₇
Therefore, 1 mole of citric acid needs 3 moles of baking soda
Molar mass of baking soda = 84g/mol
No. of moles of baking soda = mass of baking soda / molar mass of baking soda = 15g ÷ 84g/mol = 0.178 moles
Thus no. of moles of citric acid required = (1 ÷ 3) × 0.178mole =0.06mole
Molarity = no. of moles of / volume (in mL) x 1000
Volume of citric acid solution required= (0.06mole ÷ 0.8M) × 1000ml
=75ml
Learn more about molarity here:
https://brainly.com/question/8732513
#SPJ4
