Two identical charges are placed 20 cm apart and the Coulomb force they exert on each other has a magnitude of F

Respuesta :

The correct answer is 3.5 × 103 N .

F = k|q1| |q2|r2

= (8.99 × 109 N·m2C2 )

(7.369 × 10−18 C)(7.369 × 10−18 C)

(1.18 × 10−14 m)2

= 3.5 × 103 N .

what is  Coulomb force?

Coulomb's inverse-square law, sometimes known as Coulomb's law, is a physical experiment that calculates the amount of force between two stationary, electrically charged particles. The electric force between two charged things at rest is sometimes referred to as electrostatic force or Coulomb force. Although the rule existed prior to 1785, it was published for the first time by French physicist Charles-Augustin de Coulomb, hence the name. Coulomb's law was critical to the development of electromagnetic theory, perhaps even its beginning point, because it allowed for meaningful discussion of the quantity of electric charge.

According to the law, the magnitude of the electrostatic force of attraction or repulsion between two point charges is precisely proportional to the product of charge and charge magnitudes.

learn more about Coulomb force  refer:

https://brainly.com/question/66110

#SPJ4