Respuesta :
Answer:
The probability of getting a number greater than two or an odd number :
[tex]= \frac{5}{6}[/tex]
Step-by-step explanation:
the sample space is {1 , 2 , 3 , 4 5 , 6}
• let A be the event “getting a number greater than two“
Then
A = {3 , 4 , 5 , 6}
Then
p(A) = 4/6 = 2/3
• let B be the event “getting an odd number“
Then
B = {1 , 3 , 5}
Then
p(B) = 3/6 = 1/2
We notice that The event “getting a number greater than two or an odd number” is the event A∪B.
Then
p(getting a number greater than two or an odd number)
= p(A∪B)
= p(A) + p(B) − p(A∩B)
Calculating p(A∩B) :
A = {3 , 4 , 5 , 6} and B = {1 , 3 , 5}
Then
A∩B = {3 , 5}
Then
p(A∩B) = 2/6 = 1/3
Conclusion :
p(A∪B)
= p(A) + p(B) − p(A∩B)
= 2÷3 + 1÷2 − 1÷3
= 1÷3 + 1÷2
= 5÷6
The probability of getting a number greater than two or an odd number is 0.8.
We have a roll die.
We have to find the probability of getting a number greater than two or an odd number.
Assume that -
Event 'A' = Getting a number greater than two or an odd number. Then, what is the formula to find the probability of occurrence of Event 'A' ?
The formula to calculate the probability of occurrence of an event 'A' can be written as -
P(A) = [tex]\frac{No. \;of\;possible\;outcomes}{Total\;number\;of\;outcomes}[/tex]
According to question -
For getting a number greater than two or an odd number, the total number of possible outcomes are - 5.
For rolling a die, the number of outcomes will be - 6
Hence, the probability of occurrence of Event A will be -
P(A) = [tex]\frac{5}{6}[/tex] = 0.8
Hence, probability of getting a number greater than two or an odd number is 0.8.
To solve more questions on finding the probability of occurrence of certain event, visit the following link -
brainly.com/question/24028840
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