Respuesta :

The weight in grams of a double helical dna molecule stretching from the earth to the moon (`320000km) is   0.91 grams.

Given, length of a single base pair [tex]$=0.34 \mathrm{~nm}$[/tex].

So, to cover [tex]$320000 \mathrm{~km}$[/tex], total number of base pairs needed [tex]$=\frac{320000 \times 10^{3}}{0.34 \times 10^{-9}}=9.41 \times 10^{17}$[/tex](From unitary method) Mass of 1000 base pairs [tex]$=10^{-18}$[/tex]

So, mass of a single pair [tex]$=\frac{10^{-18}}{1000}=10^{-21}$[/tex]

Now, since we have total number of pairs [tex]$=9.41 \times 10^{17}$[/tex],

Total mass [tex]$=9.41 \times 10^{17} \times 10^{-21}=9.41 \times 10^{-4} \mathrm{Kg}$[/tex]

So, the total weight of a double stranded DNA molecule stretching from the earth to the moon is [tex]$0.941$[/tex] grams.

What is the Application of unitary method?

  • We are aware of the DNA's base pair length, mass, and number of bases.
  • Now we need to figure out how much base pair mass is needed to get from the earth to the moon.
  • First, we'll determine how many base pairs are needed to orbit the moon.
  • The total mass of the base pairs will then be determined.
  • A unitary method application is needed.

To learn more about unitary method visit:

https://brainly.com/question/22056199

#SPJ4

Otras preguntas