Respuesta :
The answer is -Energy released after alpha decay is 503.23 GJ.
Energy during a alpha decay is calculated using the formula -[tex]E =[/tex]Δ[tex]mC^2[/tex]
Where Δm is the mass defect
C is the speed of light
Calculate the mass defect when Pu-239 undergoes alpha decay.
- Alpha particle is same helium nucleus, thus when Pu-239 undergoes alpha decay, it releases alpha particle and thus the atomic number of new atom, U-235 is 2 less than 94 and its mass number is 4 less than 239 .
- Now, mass defect is the difference between the expected mass of nucleus and the actual mass of the atom. Thus, mass defect is-
Δm = [tex]239.052163 -235.0439299 - 4.0026 = 0.0056331\ amu[/tex]
- Next, using the formula of energy, calculate the amount of energy release per atom is
[tex]E = 0.0056331*931\ MeV = 5.24442\ MeV[/tex]
- To calculate the energy released per moles, calculate the above energy by Avogadro's number-
[tex]E = 5.24442\ Mev * (6.022 * 10^2^3) = 31.582 *10^2^3\ MeV[/tex]
- Next, convert MeV into J
[tex]1 MeV = 1.6 *10^-^1^9\ J[/tex]
This, energy released is-
[tex]E = 31.582 *10^2^3\ MeV * (1.6 *10^-^1^9) = 503.23 * 10^9 J\\E = 503.23\ GJ[/tex]
- Hence, energy released after alpha decay is 503.23 GJ.
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