Respuesta :
The answer is- Cell potential = 1.12 V
Nernst equation: Cell potential is the potential difference between two electrodes of a cell and is calculated using the Nernst equation.
Explain the Nernst equation.
- According to Nernst equation:
[tex]\[{{\rm{E}}_{{\rm{cell}}}}{\rm{\; = }}{{\rm{E}}^{\rm{0}}}{\rm{\;- }}\left[ {\frac{{0.0591}}{{\rm{n}}}} \right]{\rm{ log\ Q }}\][/tex]
Where,
Ecell = Cell potential
E0 = Cell potential under standard conditions
n = number of electrons involved in the reaction of cell.
Q = reaction quotient
- Now, the given cell reaction is-
[tex]Zn + Cu^{+2}[/tex]→[tex]Zn^{+2} + Cu[/tex]
- [tex]Zn/Zn^{+2}[/tex] acts as anode and [tex]Cu/Cu^{+2}[/tex] acts as cathode.
- E° 1.1 V
- The Nernst equation is expressed as-
[tex]\[{{\rm{E}}_{{\rm{cell}}}}{\rm{\; = }}{{\rm{E}}^{\rm{0}}}{\rm{\;- }}\left[ {\frac{{0.0591}}{{\rm{n}}}} \right]{\rm{ log\ \frac{[Zn^{2+}]}{[Cu^{2+}]} }}\][/tex]
- Putting all the data, cell potential is calculated as-[tex]E_{cell} = 1.1 V - [\frac{0.0591}{2} ] log [\frac{0.11\ M}{0.51\ M} ]\\\\ E_{cell} = 1.1\ V- (-0.02\ V) = 1.12\ V[/tex]
- Hence, the potential of the given cell = 1.12 V.
To learn more about cell potential, visit:
https://brainly.com/question/2615553
#SPJ4
