The correct answer is as follows:
a. 2 MnO₄⁻ (aq) +3 C₂O₄²⁻(aq) +
b. 0 H⁺(aq) + 4OH⁻ (aq) +
c. 0 H₂O(l) → 2 MnO₂(s) +
d. 6CO₃²⁻(aq) + 0 H⁺(aq) +
e. 0 OH⁻(aq) + 2H₂O(l)
Chemical equations exist as a representation of a reaction in its numerical and chemical formula formation.
At first, you write the skeleton chemical equation and then balanced it by utilizing an ion-electron approach.
Permanganate ion reacts in the basic medium by the following
MnO₄⁻ + 2H₂O +3e⁻ → MnO₂ + 4 OH⁻ ------------(i)
MnO₄⁻ acts as an oxidizing agent which oxidized oxalate ions into carbonate ions and lowered itself into solid MnO₂.
C₂O₄²⁻ + 4 OH⁻ → 2 CO₃²⁻ + 2e⁻ + 2H₂O ------------(ii)
Multiplying equation (i) by factor 2 and equation (ii) by factor 3 rewrite the equation as
2 MnO₄⁻ + 4 H₂O +6 e⁻ → 2 MnO₂ + 8 OH⁻ ---------------(iii)
3 C₂O₄²⁻ + 12 OH⁻ → 6 CO₃²⁻ + 6 e⁻ + 6 H₂O ------------(iv)
Adding both the equation (iii) + (iv), we get
2 MnO₄⁻ + 3 C₂O₄²⁻ + 4 OH⁻ → 6 CO₃²⁻ + 2 MnO₂ + 2 H₂O.
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