Consider the signal x(t) = e-5tu(t -1), and denote its Laplace transform by X(s). (a) Using eq. (9.3), evaluate X(s) and specify its region of convergence. (b) Determine the values of the finite numbers A and to such that the Laplace transform G(s) of g(t) = Ae-51 u(-t-to) has the same algebraic form as X(s). What is the region of convergence corresponding to G(s)?

Respuesta :

The region of convergence corresponding to G(s) will be To = -1 and A = 1

How to illustrate the information?

Based on the information given, it should be noted that the value when we evaluate X(s) and specify its region of convergence will be:

X(s( = e^(5 + 5)/(5+5)

= -5.

The region where the function exists in the transfer function's pole/zero plot is known as the Region of Convergence. We prefer to deal with rational functions for the purpose of practical filter design, which may be defined by two polynomials, one for identifying the poles and the other for calculating the zeros, respectively.

The values of the finite numbers A and to such that the Laplace transform G(s) of g(t) = Ae-51 u(-t-to) has the same algebraic form as X(s) will be - 1 and the region of convergence corresponding to G(s) is 1.

Therefore based on the information, the region of convergence corresponding to G(s) will be To = -1 and A = 1.

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