The answer is [tex]18 \mathrm{dm}^{2}[/tex]
According to question given that the area of the triangle is[tex]12dm^2[/tex]
Perimeter is equal
[tex]$\begin{aligned}&3 \mathrm{x}=6 \mathrm{a} \\&\mathrm{x}=2 \mathrm{a}\end{aligned}$[/tex]
Area of equilateral triangle [tex]$\Delta=\frac{\sqrt{3}}{4} x^{2}=12 \mathrm{dm}^{2}$[/tex]
Area of hexagon [tex]$=6 \frac{\sqrt{3}}{4} \times a^{2}=6 \frac{\sqrt{3}}{4}\left(\frac{x}{2}\right)^{2}$[/tex]
[tex]=\frac{6}{4}\left(\frac{\sqrt{3}}{4} \times \mathrm{x}^{2}\right)=\frac{6}{4} \times 12=18 \mathrm{dm}^{2}[/tex]
What is an equilateral triangle?
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