professor smith ran a simple regression equation using midterm exam scores to predict final exam scores. the r square was 0.91 and this was statistically significant (p

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10-08-2022
Mathematics

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professor smith ran a simple regression equation using midterm exam scores to predict final exam scores. the r square was 0.91 and this was statistically significant (p

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tanvigupta426 tanvigupta426 · Answer 1 · 2022-08-16T07:16:59+02:00

The the final exam score according to the linear equation is 69. Thus, Option A is correct.

According to the statement

we have to find that the exam of the midterm which is Y with the help of the given equation.

So, For this purpose, we know that the

The value of p is 0.0001 and the given equation is Y=1.5 + .9(75).

Which is a linear equation.

So,

A linear equation is an algebraic equation of the form y=mx+b. involving only a constant and a first-order (linear) term, where m is the slope and b is the y-intercept.

So, From given equation

Y=1.5 + .9(75).

Solve this equation

Y = 1.5 + 67.5

Y = 69.

So, The the final exam score according to the linear equation is 69. Thus, Option A is correct.

Learn more about Linear equation here

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Question:

Professor Smith ran a simple regression equation using midterm exam scores to predict final exam scores. The R square was 0.91 and this was statistically significant (p=0.0001). Using the following simple regression equation generated by Professor Smith, predict the final exam score Y when the midterm score is 75: Y=1.5 + .9(75).

A. 69

B. 55

C. 82

D. 91

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