The required answers are-
a. The expression for V(x) = x(9 - x)²
b. The volume of the box when x = 1 is 64 cubic square.
c. The reasonable domain for V is x ∈ [0,9].
Volume is a measure of occupied three-dimensional space. It is often quantified numerically using SI derived units or by various imperial units.
Now, the given dimension of cupboard square is 9 inch by 9 inch.
and, the cutout side length be x inch.
So, the length of the box is (9 -x) inch
the width of the box is (9 -x) inch and
the height of the box is x inch
a. Expression for V(x).
∴The volume of the box, V(x) = (length)*(width)*(height).
⇒The volume of the box, V(x) = x*(9 -x)*(9 -x)
⇒The volume of the box, V(x) = x(9 -x)²
b. volume of the box when x = 1
Put x = 1 in V(x)
V(1) = 1(9 -1)²
V(1) = 8²
V(1) = 64 cubic inches
c. reasonable domain for V
V(x) = x(9 -x)²
y = x(9 -x)²
x(9 -x)² ≥ 0
⇒ x ≥ 0
⇒(9 -x)² ≥ 0
⇒9 -x ≥ 0
⇒ x ≤ 9
⇒ x ∈ [0,9]
So, reasonable domain for V is x ∈ [0,9]
Hence,The required answers are-
a. The expression for V(x) = x(9 - x)²
b. The volume of the box when x = 1 is 64 cubic square.
c. The reasonable domain for V is x ∈ [0,9].
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