The area of the parallelogram will be 56.5 square units.
The space occupied by any two-dimensional figure in a plane is called the area. The area of the outer surface of any body is called the surface area.
The vertices of the trapezoid are (x₁, y₁), (x₂, y₂), (x₃, y₃), and ( x₄, y₄).
Then the area of the trapezoid will be calculated as below:-
Area = 1/2 |[(x₁y₂ + x₂y₃ + x₃y₄+x₄y₁) - (y₁x₂ + y₂x₃ + y₃x₄+y₄x₁)]|
We have
(x₁, y₁) ⇒ ( -5,5 )
(x₂, y₂) ⇒ ( 3,2 )
(x₃, y₃) ⇒ ( 0,2 )
(x₄, y₄) ⇒ ( -13,-11 )
Then the area will be calculated as below:-
Area = 1/2[{(-5) x (2) + (3) x (2) + (0) x (-11) + (-13) x ( 5 )} – {(5) x (3) + (2) x (0) + (2) x (-13) + (-11 ) ( -5 )}]
Area = 113 / 2
Area = 56.5 square units.
Therefore, the area of the trapezoid will be 56.5 square units.
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