She can choose 10 different pairs of fruits.
With five different fruits, the first (apple) can be matched with each of the other five. That’s 4 pairs.
The second fruit (orange) can also be matched with each of the other four fruits, except that it has already been matched with an apple, so that would not be a “different” pair. So that’s 3 more pairs.
The third fruit (pear) can make 2 more “different” pairs, the fourth fruit (strawberry) can make 1 more unique pairs.
This implies 4 + 3 + 2 + 1 = 10 pairs
Or we can use combinations for this:
⁵C₂ = 5! / 2! × 3!
= 5 × 4 × 3! / 2 × 3!
= 10 pairs
To learn more about combinations from the given link
https://brainly.com/question/23346126
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