t’ = 22.6 years The half-life of curium-243
Assuming that the radioactive decay of Curium is of 1st order, therefore the rate equation is in the form of:
A = Ao e^(-kt)
where,
A = amount after t years = 2755
Ao = initial amount = 3312
k = rate constant
t = number of years passed = 6
Therefore the rate constant is:
2755/3312 = e^(-6k)
-6k = ln (2755/3312)
k = 0.0307/yr
The half life, t’, can be calculated using the formula:
t’ = ln 2 / k
Substituting the value of k:
t’ = ln 2 / 0.0307
t’ = 22.586 years
or
t’ = 22.6 years
Is curium used in bombs?
Curium isotopes have been detected in the fallout regions of US nuclear hydrogen bomb test sites, and in spent nuclear fuel. Uses of curium are limited, but it served as a source of α-particles on the X-ray spectrometer on several Mars Rovers.
What does curium do to the body?
It tarnishes rapidly in air. Curium has been used to provide power to electrical equipment used on space missions. Curium has no known biological role. It is toxic due to its radioactivity.
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