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The square armature coil of an alternating current generator has 200 turns and is 20.0 cm on side. When it rotates at 3600 rpm, its peak output voltage is 120 V. (a) What is the frequency of the output voltage

Respuesta :

The frequency of the output voltage is 60 Hz.

Given data:    

  • Number of turns, N = 200
  • Length of the side, l = 20 cm = 0.2 m
  • Speed if rotation, w = 3600 rpm
  • Voltage, V = 120 V
  • Speed from rpm to rad/s

3600 * (2π/60)

3600 * 0.10473

3600 rpm = 377 rad/s

  • Frequency of output,

f = w/2π

f = 377 / 6.284

f = 59.99 Hz or approximately, 60 Hz.

To learn more about square armature coil: https://brainly.com/question/17184104

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