A bag contains 5 white, 3 black, and 2 green balls. Balls are picked at random. Explain why the events picking a white ball and then another white ball without replacement are dependent. Then, identify the probability.

Respuesta :

The probability of picking a black ball and then another black ball is; Due to conditional probability and is equal to 1/15.

How to solve conditional probability?

  • The probability of one event is affected or depends on the probability of another event in contingent probability.

Now, the total balls in the bag are:

  • Total balls = 5 + 3 + 2
  • Total balls = 10 balls

The probability of first picking a black ball is:

  • P(black ball first) = 3/10

Now, when a black ball is picked, there will be 9 balls left in the bag of which only 2 are black.

Thus, the probability of picking another black ball is:

  • P(black ball second) = 2/9

Thus; the probability of picking a black ball and then another black ball is;

  • P(black ball | black ball) = 3/10 × 2/9
  • P(black ball | black ball) = 1/15

Therefore, the probability of picking a black ball and then another black ball is; Due to conditional probability and is equal to 1/15.

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