If a polynomial function, f(x), with rational coefficients has roots 3 and startroot 7 endroot, what must also be a root of f(x)? negative startroot 7 endroot i startroot 7 endroot –3 3i

Respuesta :

The root of f(x) will be (A) -√7.

What is a polynomial function?

  • A polynomial function is one that involves only non-negative integer powers or positive integer exponents of a variable in an equation such as the quadratic equation, cubic equation, and so on.
  • For example, 2x+5 is a polynomial with an exponent of one.

To find the root of f(x):

  • A polynomial function f(x) has roots 3 and √7.
  • 3 is a real number.
  • √7 is an irrational number.
  • The zeros or root of the function always occurs in conjugate pair.

Conjugate pair: A root has two forms one positive and one negative.

Example: a + √b, a - √b

  • For the given function f(x), √7 should be in conjugate pair.
  • One more possible root would be √7.

Therefore, the root of f(x) will be (A) -√7.

Know more about polynomial functions here:

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The correct question is given below:

If a polynomial function f(x) has roots 3 and a square root of 7 what must also be a root of f(x)?

A. negative square root of 7

B. i square root of seven

C. –3

D. 3i

Answer:

A

Step-by-step explanation: